In a specific beverage, the volume ratio of flavoring to sugar to water is 3 : 12 : 60. The beverage will be modified so that the ratio of flavoring to sugar is reduced by half, while the ratio of sugar to water is increased by a factor of two. If the modified beverage contains 6 ounces of sugar, how many ounces of water will it have?
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Thankss
thanks
wait, so the flavoring:sugar ratio is 3:12 = 1:4 and we cut that in half to 1:8? and sugar:water 12:60=1:5 doubled to 2:5? that gave me a fraction, is that right lol
yeah the wording is annoying but "reduced by half" means multiply the ratio by 1/2, so flavoring:sugar becomes 1:8. then just use the given sugar to get water
This one tripped me up because I applied the halving to the wrong pair. Read carefully which ratio they modify!
same. i doubled the sugar:water first and got confused when nothing matched an answer choice
thanks, super clear once you set up the two new ratios separately.
Is 6 ounces of sugar the actual sugar in the modified drink or the original? The wording "modified beverage contains 6 ounces of sugar" suggests it's the new one right? helped me a lot once I caught that.
What it tests
Your ability to convert between fractions, ratios, and decimals and to reason proportionally.
Common trap
Cross-multiplying incorrectly or mixing up the ratio parts — a part:part ratio is not a fraction of the whole.