In an online game, the number of active players reduces by 20% every 4 years. If there are currently 80,000 active players, how many active players will remain after 12 years?
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Great
appreciated!
I picked A at first because I just did 80,000 x 0.2 and panicked lol. took me a sec to remember it's the REMAINING amount each time, not the amount lost
classic trap, they put 16,000 there on purpose to catch that exact mistake
thanks this was helpful, kept forgetting to count how many 4-year chunks fit into 12
What it tests
Your ability to reason about weighted averages and the composition of mixtures.
Common trap
Averaging the percentages of two solutions without weighting by their volumes.