A club is planning to combine 30 pounds of candy priced at $9.00 per pound with another type of candy that costs $4.00 per pound in order to achieve an overall cost of $7.00 per pound for the mixture. How many pounds of the $4.00 per pound candy should be included?
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good question
Thanks for sharingThank you for sharing!!thanks for sharing
wait how do you set this up? I keep wanting to just average 9 and 4 lol
you have way more of the expensive candy so the average pulls toward 9, not the middle. think weighted.
Got it in like 30 seconds, these mixture ones are basically free points if you stay organized
the $7 target is below $9 so you def need a decent amount of the cheap stuff to drag it down. just set the total cost equal both ways and solve for x
that's the part that tripped me up, I forgot the 30 lbs is already fixed. thanks!
same, once I saw the answer was more than 30 it clicked that the cheap candy has to outweigh the expensive one
What it tests
Your ability to reason about weighted averages and the composition of mixtures.
Common trap
Averaging the percentages of two solutions without weighting by their volumes.