In the sequence 480, 240, 120, 60, each term is half of the previous term. What is the smallest term in the sequence that exceeds 1?

Answer Choices

Correct answer marked below

64/15

32/15

15/8

Correct

15/4

15/2

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Explanation

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Official Explanation

Official

The sequence starts with 480, 240, 120, 60, and continues as follows: 60/2, 60/4, 60/8, 60/16, etc. We find that 60/32 = 15/8, which is greater than 1, while 60/64 = 15/16 is less than 1. Therefore, the smallest term greater than 1 is 60/32 = 15/8. However, if we need…

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Comments

RosanneDec 28, 2024

still struggling with these types of problems

MeghnaAug 21, 2024

Great

SachiMay 29

wait why is 15/8 the answer? i got 15/4 but that's not even an option. did i count wrong?

SalehJun 12

15/4 is 3.75, which is bigger than 1, but the question asks for the smallest term that exceeds 1. so 15/8 is smaller and still >1.

ZhaohongJun 4

lol i did the same thing. you probably stopped one term early.

What this question tests

What it tests

Your ability to spot and extend arithmetic and geometric sequences and work with recursive definitions.

Common trap

Off-by-one errors in indexing (a₀ vs a₁) or confusing an arithmetic difference with a geometric ratio.