Max(x,y) is defined as the maximum of x and y, and Min(x,y) is defined as the minimum of x and y. What is the average of Max(x,60) and Min(40,x) ?
(1) Min(x, 60) = x
(2) Max(40, x) = x

I got C. Statement 1 tells me x ≤ 60, but that still allows x < 40, so the expression might depend on x. Statement 2 says x ≥ 40, but doesn't cap x above. Together they give 40 ≤ x ≤ 60, and then it seems like the average becomes constant. Does that make sense?

Is it just me or is statement 1 actually x < 60? Min(x,60)=x means x is the smaller one, so x ≤ 60. That includes x=60. But then if x=30, Max(30,60)=60 and Min(40,30)=30, average 45. If x=50, average 50. So not sufficient. Statement 2 alone: x ≥ 40. If x=40, Max(40,60)=60, Min(40,40)=40, avg 50. If x=70, Max(70,60)=70, Min(40,70)=40, avg 55. So not sufficient. Together: 40≤x≤60 gives 50. Answer C.

This one tripped me up because I forgot that Max and Min just pick the larger/smaller, and the average of two numbers is fixed once you know which is which. Once I realized that, it became straightforward.

Took me a while but I finally see why the answer is C. At first I thought statement 2 alone might be enough because x≥40, but then x could be huge, making Max(x,60)=x and the average depend on x. So yeah, need both.