Free Practice Question
PS · Problem Solving
655-705
Combinations
Given eleven positive real numbers n1 < n2 < n3 < ... < n11, how many triplets can be formed such that in each triplet the first number is less than the second, and the second is less than the third?
Answer Choices
Sign in to reveal the correct answerA
55
B
110
C
165
D
220
E
275
Reveal the correct answer
Sign in for free to check your answer and unlock the full explanation.
Track your performance and improve
Get detailed analytics, unlock full explanations, and move up difficulty tiers as you practice.
Explanation
Unlock the full explanation
Create a free account to reveal the correct answer, see the step-by-step explanation, and start tracking your GMAT progress.
Comments
Sign in to join the discussion
No comments yet
Be the first to share your thoughts and help others understand it better.
Sign in to commentDetails
Difficulty
655-705
Type
PS
Category