Very Hard - 705+ Exponents/Powers Problem Solving GMAT Questions
Very Hard - 705+ difficulty Exponents/Powers Problem Solving GMAT practice questions. Every question below links to its own page with the full solution, community comments, and discussion.
Practice Very Hard - 705+ Exponents/Powers Problem Solving questions
Very Hard - 705+ Exponents/Powers Problem Solving questions measure your grasp of exponent rules — multiplying and dividing powers, power-of-a-power, and negative/zero exponents.. Here you'll find 8 free questions in this band — every one shows the correct answer, with full step-by-step solutions available once you sign in for free. Practice in this difficulty range to build speed and accuracy, then move up a tier as your scores improve.
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Are these Exponents/Powers Problem Solving questions free?▾
Yes. All 8 questions in this collection are free to practice. Each question shows the correct answer, and signing up for a free account unlocks the complete step-by-step explanations.
What does Very Hard - 705+ difficulty mean on the GMAT?▾
The 705-805 band maps to the GMAT Focus scoring range. Questions in this band are very hard - 705+ — ideal for building accuracy before you move up to harder tiers.
Latest Community Comments
recent discussion across these questionsI think the answer is 11. The digit sum is 2. Possible digit multisets: {2,0,0,...,0} and {1,1,0,...,0}. For the first, the 2 must be the first digit (since if it's not, the number would start with 0, which is not allowed for an 11-digit number). So 1 number. For the second, the first digit must be 1 (can't be 0), and the other 1 can be in any of the remaining 10 positions. So 10 numbers. Total 11. But is there any other combination? What about {1,0,1,0,...}? That's the same as two 1s. So 11.
onProblem Solving · Exponents/Powers—If n is an integer such that the sum of the digits of n is 2, and 10^1...This is way too hard for me. I got p = 2^-25 and then got stuck. Respect to anyone who solves this in 2 minutes.